Asked by billy
What roots does x^3 - 6x^2+3x-10 have?
Answers
Answered by
drwls
Solve for the first root by graphing, using the "p/q rule", or trial and error. I will try the latter.
By inspection, I see that one root of the equation
x^3 - 6x^2+ 3x -10 = 0
is x = -1. Therefore (x+1) is a factor
Now divide x+1 into x^3 - 6x^2+ 3x- 10 using polynomial long division and get a quadratic that must be zero. I get
x^2 -7x -10 = 0. Factor that for the remaining roots
By inspection, I see that one root of the equation
x^3 - 6x^2+ 3x -10 = 0
is x = -1. Therefore (x+1) is a factor
Now divide x+1 into x^3 - 6x^2+ 3x- 10 using polynomial long division and get a quadratic that must be zero. I get
x^2 -7x -10 = 0. Factor that for the remaining roots
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