Asked by maxamillion
a block of stone has a density of 2.75 g/cm3. the block has a mass of 3.30 kg. it measures 6.00 cm wide by 8.00 cm high by L cm long.
if i found L to be 68.6927cm by doing m=D*V, is that right? Also if it was in fresh water (density=1000kg/cm^3), would the buoyant force be 32,313,050? I feel like that number is WAYY too big, but i did Fb=pgV and that's what I got. Help please!!
if i found L to be 68.6927cm by doing m=D*V, is that right? Also if it was in fresh water (density=1000kg/cm^3), would the buoyant force be 32,313,050? I feel like that number is WAYY too big, but i did Fb=pgV and that's what I got. Help please!!
Answers
Answered by
Scott
watch your sig figs
you're mixing g and kg
also , water density is 1000 kg/m^3
... or 1 g/cm^3
V = 3300 g / 2.75 g/cm^3
convert V to m^3 and use 9.81 for g
... Fb will be in Newtons
you're mixing g and kg
also , water density is 1000 kg/m^3
... or 1 g/cm^3
V = 3300 g / 2.75 g/cm^3
convert V to m^3 and use 9.81 for g
... Fb will be in Newtons
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