Asked by bill

A supertanker (mass = 1.57E+8 kg) is moving with a constant velocity. Its engines generate a forward thrust of 7.47E+5 N. Determine the magnitude of the resistive force exerted on the tanker by the water.

7.47×10^N is correct, but I need to know how
Answered by Scott
constant velocity (not accelerating), means the the thrust equals the resistive force
Answered by Henry
M = 1.57*10^8 kg.
Ft = 7.47*10^5 N.
Fr = ?.

Ft-Fr = M*a.
Ft-Fr = M*0,
Ft-Fr = 0,
Fr = Ft = 7.47*10^5 N.
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