Well, in theory
a) F * 0.15 = 25
b)F * .15 sin 30 = 25
but we know sin 30 = 1/2
so
F * .075 = 25
The oil drain plug on a car's engine has just been tighten to a torque of 25m*N.
a) if a 0.15m long wrench is used to change the oil, what is the minimum force needed to loosen the plug?
b) due to limited workspace, it will be necessary to crawl under the car. the force cannot be applied perpendicularly to the length of the wrench. if the applied force makes a 30-degree angle with the length of the wreach, what force is required to loosen the drain plug?
how do I do this???
1 answer