Question
A sled slides without friction down a small, ice-covered hill. If the sled starts from rest at the top of the hill, its speed at the bottom is 7.60 m/s. What is the height of the hill?
Answers
potential energy at top = kinetic energy at bottom
m g h = (1/2) m v^2
h = v^2/(2g)
h = (7.60)^2/(2*9.81)
m g h = (1/2) m v^2
h = v^2/(2g)
h = (7.60)^2/(2*9.81)
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