Asked by Gary
The three angles of a triangle are x°,
(x + 30)° , (x – 6)° . Find the dimension of each angle.
(x + 30)° , (x – 6)° . Find the dimension of each angle.
Answers
Answered by
Reiny
Isn't the sum of all 3 angles equal to 180°
well. .....
well. .....
Answered by
melvin
Miscellaneous Problem
4.) The three angles of a triangle are x , ( x+30), (x-6)
The sum of the angle of a triangle is 180.
x + (x + 30) + (x-6) = 180
x + x + 30 + x – 6 = 180
3x + 30 – 6 = 180
3x + 24 = 180
3x = 180 – 24
3x = 156
x = 52 degree
(x + 30) degree
52 + 30 = 82 degree
and
(x – 6) degree
52 – 6 = 46 degree
4.) The three angles of a triangle are x , ( x+30), (x-6)
The sum of the angle of a triangle is 180.
x + (x + 30) + (x-6) = 180
x + x + 30 + x – 6 = 180
3x + 30 – 6 = 180
3x + 24 = 180
3x = 180 – 24
3x = 156
x = 52 degree
(x + 30) degree
52 + 30 = 82 degree
and
(x – 6) degree
52 – 6 = 46 degree
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