Exactly 3.0 mol NO and 2.0 mol O2 were placed

in a 1.00-L flask. These gases react as follows:
2 NO + O2 2 NO2 .
At equilibrium, the mixture contained 2.0 mol
NO2. What is the Kc for the reaction above?
A 0.50
B 1.00
C 2.0
D 2.5
E 4.0

3 answers

I'm confused how to get this answer
This is my ice chart
2NO + O2 = 2NO2
I 3 2 -
C 2x x x
E 3+2x 2+x x
you used 1 mole NO, used .5 mole O2, and created 1 mole NO2

Kc=1^2 /(1^2*.5)= 2.0
how is .5 of o2 used?