so you want 11 of the 108 cards, which would be
C(108,11)
= appr 3.4 x 10^14
quite a few i would say
Canasta is played with two decks of 52 cards each plus the 4 jokers. A standard Canasta hand consists of 11 cards. How many hands are possible?
4 answers
C(54,11) are duplicates
what about duplicate cards? There are two of each card, and 4 jokers.
Thanks Steve, you are right, I missed the duplications
I was thinking something along the lines of dividing by 2^52 , since we have pairs 52 times.
I don't know enough about jokers. Are the all the same or distinct?
I did count them in my 108 = 2x52+4
If they are the same, we have to divide by another 4!
I was thinking something along the lines of dividing by 2^52 , since we have pairs 52 times.
I don't know enough about jokers. Are the all the same or distinct?
I did count them in my 108 = 2x52+4
If they are the same, we have to divide by another 4!