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Original Question
What is the normal force when a 40 kg person jumps and is accelerating at 3 m/s2 upward while in contact with the ground?Asked by Naren
What is the normal force when a 40 kg person jumps and is accelerating at 3 m/s2 upward while in contact with the ground?
Answers
Answered by
Damon
F is up, +
F - m g = m a
F = m(g+a) = 40 (9.81+3)
F - m g = m a
F = m(g+a) = 40 (9.81+3)