Asked by Anonymous
10x+10y+20=1850
20x+20y+10z=2200
20x+10y+10z=1500
20x+20y+10z=2200
20x+10y+10z=1500
Answers
Answered by
Damon
I bet you mean
10x+10y+20z=1850
20x+20y+10z=2200
20x+10y+10z=1500
get rid of x and y in first two by multiplying first eqn by 2
20x+20y+40z=3700
................> 30 z = 1500 so z = 50
20x+20y+10z=2200
=========================
then third and first
20x+10y+10z=1500 >> 20 x + 10 y = 1000
20x+20y+40z=3700 >> 20 x + 20 y = 1700
so
-20 y = -700
y = 35
go back and get x from anywhaere knowing y is 35 and z is 50
10x+10y+20z=1850
20x+20y+10z=2200
20x+10y+10z=1500
get rid of x and y in first two by multiplying first eqn by 2
20x+20y+40z=3700
................> 30 z = 1500 so z = 50
20x+20y+10z=2200
=========================
then third and first
20x+10y+10z=1500 >> 20 x + 10 y = 1000
20x+20y+40z=3700 >> 20 x + 20 y = 1700
so
-20 y = -700
y = 35
go back and get x from anywhaere knowing y is 35 and z is 50
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.