Asked by Tagore school bilara
Calculate the escape velocity on surface of earth of radius of moon is 1740km and Massis7.4 *10to the power 22
Answers
Answered by
Damon
F = - G m M/r^2
work done from R to infinity
F dr = G m M/R
so
G M m/R^2 = Ke at surface = (1/2)m v^2
v^2 = 2 G M/R
G = 6.67 * 10^-11
M = 7.4 * 10^22 kg
R = 1.74^10^6 meters
plug and chug
work done from R to infinity
F dr = G m M/R
so
G M m/R^2 = Ke at surface = (1/2)m v^2
v^2 = 2 G M/R
G = 6.67 * 10^-11
M = 7.4 * 10^22 kg
R = 1.74^10^6 meters
plug and chug
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.