Asked by zayn
Write the equation of a line that passes through (-4,2) and is perpendicular to 3x+6y=9
Answers
Answered by
Reiny
First of all they should have reduced your given 3x+6y=9
to x + 2y = 3
quickest way:
since the new equation is perpendicular to the old one, it
should be
2x - y = c , (realizing that for ax + by = c, the slope is -a/b )
plug in your point (-4,2)
-8 - 2 = c
c =-10
new equation: 2x - y = -10
to x + 2y = 3
quickest way:
since the new equation is perpendicular to the old one, it
should be
2x - y = c , (realizing that for ax + by = c, the slope is -a/b )
plug in your point (-4,2)
-8 - 2 = c
c =-10
new equation: 2x - y = -10
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