Asked by jessica
) If the loss of each electron represents the liberation of 1.875 x 10-19 J, calculate the number of kJ and Cal (kcal), of fructose and oleate in a 1.00 g sample. (Significant digits count.)
Fructose
kJ = _____________
Cal = _____________
oleate
kJ = _____________
Cal = _____________
Fructose
kJ = _____________
Cal = _____________
oleate
kJ = _____________
Cal = _____________
Answers
Answered by
DrBob
This is stated in such a way it doesn't make sense to me.
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