Asked by Sarayu
In the triangle ABC, point M is the midpoint of AB, point D belongs to AC so that AD:DC=2:5. If the Area of ABC = 56 yd^2, find the Area of BMC, Area of AMD, and the Area of CMD.
Answers
Answered by
Reiny
Since M is the midpoint,
area AMC = area BMC , they have the same height and base
so BMC = (1/2)(56) = 28
now look at triangles AMD and CMD, they have the same height and their bases are in the ratio of 2 : 5
so triangle AMD = (2/7)(28) = 8
and triangle CMD = (5/7)(28) = 20
area AMC = area BMC , they have the same height and base
so BMC = (1/2)(56) = 28
now look at triangles AMD and CMD, they have the same height and their bases are in the ratio of 2 : 5
so triangle AMD = (2/7)(28) = 8
and triangle CMD = (5/7)(28) = 20
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