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In the following reaction, first find how many oxygen molecules would be used to completely react with 230 grams of pentyl alco...Question
In the following reaction, first find how many oxygen molecules would be used to completely react with 230 grams of pentyl alcohol (C5H11OH)? Then, if exactly 1.505x10^21 carbon dioxide molecules were formed in this reaction, calculate the grams of water formed during this reaction. C5H11OH+O2 ---->CO2+H2O
Answers
Steve
230g of compound is 230/88.15 = 2.609 moles
The balanced equation is
2C5H11OH + 15O2 ----> 10CO2 + 12H2O
So, you will need 15/2 * 2.609 * 6.02*10^23 = 1.78 * 10^25 molecules of O2
1.505*10^21 = 0.0025 moles CO2
So, you'd have produced 12/10 * 0.0025 * 18.02 = 0.054 g H2O
The balanced equation is
2C5H11OH + 15O2 ----> 10CO2 + 12H2O
So, you will need 15/2 * 2.609 * 6.02*10^23 = 1.78 * 10^25 molecules of O2
1.505*10^21 = 0.0025 moles CO2
So, you'd have produced 12/10 * 0.0025 * 18.02 = 0.054 g H2O