Ask a New Question

Asked by tom

y= -2cos(pi/6) + 8

whats the maximum and minimum?
7 years ago

Answers

Answered by Steve
Assuming you meant

y= -2cos(pi/6 x) + 8

then the center line is at y=8
and the amplitude is 2

so, what do you think?
7 years ago
Answered by tom
min is 6 and max is 10?
7 years ago

Related Questions

given x=2cos(t)+t*sin(t) and y=2sin(t)-t*cost(t), with t:[pi, 2pi] find all critical values. b... given x=2cos(t)+t*sin(t) and y=2sin(t)-t*cost(t), with t:[pi, 2pi] find all critical values. (4 an... 2cos^2+sin=1 Given that Sin(A+B)=2Cos(A-B) and tan A = 1/3 , Find the exact value of tan B. Given f(x)=sin(x)-2cos(x) on the interval [0,2pi]. a) Determine where the function is increasing... Why does cos^2(x)= 1/2cos(2x)+1/2? I am trying to integrate, but the answer key says to first rewrit... 2cos(45)-tan(45)/90.5-64 =? If x=2cos (z) and y= sin (z), then d^2y/dx^2=? What I got -sin (z) / -8cos (z)*sin (z) simplifie... y=1/2cos[1/2(x-30)]-5 has a transformed point of
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use