Vertical problem:
(1/2) m V^2 = m g h
V = sqrt (2 g h) at bottom
V =sqrt(2*9.81*180.6
time at ground:
average v = V/2
so
t = 180.6/v = time at ground
Horizontal problem (use t from above)
a = 13.0/2.63
u = a t
d = (1/2) a t^2
speed = sqrt(u^2+V^2)
A 2.63 kg ball is dropped from the roof of a building 180.6 m high. While the ball is falling to Earth, a horizontal wind exerts a constant force of 13.0 N on the ball. How long does it take to hit the ground? The acceleration of gravity is 9.81 m/s2 .
How far from the building does the ball hit the ground?
What is the speed when it hits the ground?
1 answer