Question

A gas is kept at a pressure of 4.00 × 105 Pa and a temperature of 30.0 °C. When the pressure is
reduced to 3.00 × 105 Pa and the temperature
raised to 40.0 °C, the volume is measured to be
0.45 × 10^−4 m^3. Estimate the original volume of the gas.

I tried using initial (PV/T) = final (PV/T), but it didn't work. The book says the answer is 1.1 × 10^–5 m^3

Answer 1

did you remember to use °K ?
Show what you did, eh?

Answer 2

Are you saying that I was doing it right, then?

I did
(4*10^5)V/303 = 3*10^5(0.45*10^-4)/313

1320.13V = 0.043
V = 0.00003267177507 m^3

Answer 3

Looks right to me.