Asked by Mariam
A shopper in a supermarket pushes a loaded cart with a horizontal force of 80.5N. If the cart has a mass of 33.8kg, how far will it move in 1.31s, starting from rest? The coefficient of friction is 0.12
Answers
Answered by
Anonymous
weight = normal force = m g = 33.8 * 9.81
= 332 N
friction force = 0.12 * 332 = 39.8 N
so net force forward = 80.5 - 39.8
= 40.7 N
a = 40.7/33.8
d = (1/2) a t^2
= 332 N
friction force = 0.12 * 332 = 39.8 N
so net force forward = 80.5 - 39.8
= 40.7 N
a = 40.7/33.8
d = (1/2) a t^2
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