Asked by Maha
A student takes examination in four subjects A, B, C, D. His chance of passing in A is 4/5,in B is 3/4in C is 5/6 and in D is 2/3.To qualify he must pass in A and at least two other subjects. What is the probability that he qualifies?
Answers
Answered by
Scott
p(not pass B, C, D) = 1/4 * 1/6 * 1/3 = 1/72
p(not pass B, C) = 1/4 * 1/6 = 1/24 = 3/72
p(not pass B, D) = 1/4 * 1/3 = 1/12 = 6/72
p(not pass C, D) = 1/6 * 1/3 = 1/18 = 4/72
p(pass at least two) = 1 - 14/72 = 58/72
p(qualify) = 4/5 * 58/72
p(not pass B, C) = 1/4 * 1/6 = 1/24 = 3/72
p(not pass B, D) = 1/4 * 1/3 = 1/12 = 6/72
p(not pass C, D) = 1/6 * 1/3 = 1/18 = 4/72
p(pass at least two) = 1 - 14/72 = 58/72
p(qualify) = 4/5 * 58/72
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.