Asked by Ricky
A gun is fired, and a 50gram bullet is accelerated to a muzzle speed of 100m/s. If the length of the gun barrel is 0.90m, what is the magnitude of the accelerating force? Assume the acceleration is constant.
Help me please???
Help me please???
Answers
Answered by
Damon
acceleration = change in velocity/change in time
magnitude of change in velocity = 100 m/s
(all in one direction)
time = distance/average speed = 0.9/50
= 1.8/100 = .018
so
a = 100/.018
then
F = m a = .050*100/.018 = 278 m/s^2
which is about 28 times gravity
magnitude of change in velocity = 100 m/s
(all in one direction)
time = distance/average speed = 0.9/50
= 1.8/100 = .018
so
a = 100/.018
then
F = m a = .050*100/.018 = 278 m/s^2
which is about 28 times gravity
Answered by
Madison/Kayla
v² = 2ax
100² = 2*0.9a
a =100² /1.8 = 5555.56
Force = ma = 0.05 x 5555.56 = 278 N
100² = 2*0.9a
a =100² /1.8 = 5555.56
Force = ma = 0.05 x 5555.56 = 278 N
Answered by
Ricky
Thanks guys! I appreciate your help!
Answered by
Damon
You are welcome. Now you have two ways to do it, both valid.
Answered by
Madison/Kayla
Welcome :)
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