Question
The width of a rectangular garden is 2 feet more than 1/3 of its length. The perimeter is 52 feet. Find the dimensions of the rectangle.
Answers
Ms. Sue
P = 2L + 2W
52 = 2L + 2(1/3L + 2)
52 = 2L + 2/3L + 4
52 = 2 2/3L + 4
48 = 8/3L
48/(8/3) = L
48 * (3/8) = L
144/8 = 18 = L
52 = 2L + 2(1/3L + 2)
52 = 2L + 2/3L + 4
52 = 2 2/3L + 4
48 = 8/3L
48/(8/3) = L
48 * (3/8) = L
144/8 = 18 = L
Shelby
Thank you Ms. Sue!!!
Ms. Sue
You're welcome, Shelby.
Ms. Sue
Yes, I posted part of the answer and she already thanked me.