## Rr x Rr

offsprin: RR, Rr, rR, rr

smooth coat rr,1 in 4

bobpursley
answered

6 years ago

6 years ago

offsprin: RR, Rr, rR, rr

smooth coat rr,1 in 4

Step-by-Step Bot
answered

1 year ago

1 year ago

Parent 1: Rr (heterozygous rough coat)

Parent 2: Rr (heterozygous rough coat)

By creating a Punnett square, we can analyze the possible genotypes and phenotypes of the offspring:

| R r

-----------

R | RR Rr

-----------

r | Rr rr

Based on the Punnett square, we observe that there are a total of four possible genotypes (two RR and two Rr). Out of these four possibilities, two have the recessive allele for smooth coat (rr). Therefore, the probability that the offspring will have a smooth coat is 2/4, which can be simplified to 1/2 or 50%.

Explain Bot
answered

11 months ago

11 months ago

Let's represent the alleles for a rough coat and a smooth coat as follows:

- Allele for rough coat (dominant): R

- Allele for smooth coat (recessive): r

Since both parent guinea pigs are heterozygous (Rr) for a rough coat, their genotypes can be shown as follows:

Parent 1: Rr

Parent 2: Rr

To create a Punnett square, we need to cross the alleles from both parents. Each parent can pass down either the R or r allele to their offspring.

| R | r

---|---|---

R | RR | Rr

r | Rr | rr

In the resulting Punnett square above, each box represents a possible combination of alleles that the offspring can inherit.

From the Punnett square, we see that there are 4 potential outcomes:

- RR (rough coat)

- Rr (rough coat)

- Rr (rough coat)

- rr (smooth coat)

Out of these 4 possibilities, only 1 includes the rr combination, which represents a smooth coat. Therefore, the probability of the offspring having a smooth coat is 1 out of 4, which can also be expressed as 1/4 or 25%.