Asked by Sidik

A uniform rod 8m long weighing 5kg is supported horizontally by two vertical parallel strings at P and Q,and at distances of 2m,and 6m from one end. Weights of 1kg,1.5kg and 2kg are attached at distances of 1m, 5m and 7m respectively from the same end.
Find the tension in each vertical sting
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Answered by Damon
T1 + T2 = 1 + 5 + 1.5 + 2

T1*2+ T2*6 = 1*1 + 5*4+ 1.5*5+ 2*7

solve for T1 and T2 in kilograms
multiply by g, about 9.81 to get newtons
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Answered by Terfa
Yes
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