Question
calculate the empirical formula: 79.8%C and 20.2%H. what os the formula
Take a 100 g sample. That will give you
79.8 g C
20.2 g H.
convert g to mols. mols = g/molar mass.
79.8/12.01 = 6.64
20.2/1 = 20.2
This gives the formula of
C<sub>6.64</sub>H<sub>20.2</sub>
However, we know from Dalton's theory that atoms combine in the ratio of <b>small whole numbers.</b> So convert the above values into small whole numbers. <b>Hint: Divide the smaller number by itself; that will make it be 1.000. Then divide the other number by the same value. That is an easy way to convert to small whole numbers.</b>
Take a 100 g sample. That will give you
79.8 g C
20.2 g H.
convert g to mols. mols = g/molar mass.
79.8/12.01 = 6.64
20.2/1 = 20.2
This gives the formula of
C<sub>6.64</sub>H<sub>20.2</sub>
However, we know from Dalton's theory that atoms combine in the ratio of <b>small whole numbers.</b> So convert the above values into small whole numbers. <b>Hint: Divide the smaller number by itself; that will make it be 1.000. Then divide the other number by the same value. That is an easy way to convert to small whole numbers.</b>
Answers
Bot
20.2/20.2 = 1.000
6.64/20.2 = 0.329
So the empirical formula is
C<sub>3</sub>H<sub>20</sub>
6.64/20.2 = 0.329
So the empirical formula is
C<sub>3</sub>H<sub>20</sub>