Asked by Keonn'a: Please help me ?
Two painters can paint a room in 2 hours if they work together. The less experienced painter takes 4 hours more than the more experienced painter to finish the job. How long does it take for the less experienced painter to paint the room individually? Round to 2 decimal places.
Answers
Answered by
Reiny
rate of faster painter --- 1/x
rate of slower painter -- 1/(x+4)
combined rate = 1/x + 1/(x+4)
= (x+4 + x)/(x(x+4))
= (2x + 4)/(x^2 + 4)
1/[(2x + 4)/(x^2 + 4)] = 2
(x^2 + 4x)/(2x+4) = 2
x^2 + 4x = 4x + 8
x^2 = 8
x = √8 or appr 2.83 hrs
rate of slower painter -- 1/(x+4)
combined rate = 1/x + 1/(x+4)
= (x+4 + x)/(x(x+4))
= (2x + 4)/(x^2 + 4)
1/[(2x + 4)/(x^2 + 4)] = 2
(x^2 + 4x)/(2x+4) = 2
x^2 + 4x = 4x + 8
x^2 = 8
x = √8 or appr 2.83 hrs
Answered by
Scott
L = M + 4 ... L - 4 = M
2/L + 2/M = 1 ... 2M + 2L = L M
2(2L - 4) = L^2 - 4L ... 0 = L^2 - 8L + 8
use quadratic formula to find L
2/L + 2/M = 1 ... 2M + 2L = L M
2(2L - 4) = L^2 - 4L ... 0 = L^2 - 8L + 8
use quadratic formula to find L
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