Asked by Brittany
Two dogs are playing tug-o-war. The first dog pulls with the force of 400N and the second dog is hanging on but is being pulled towards the first dog at a constant velocity. What is the force of friction between the second dog's feet and the ground?
Answers
Answered by
Henry
400-Fk = M*a.
400-Fk = M*0 = 0
Fk = 400 N.
400-Fk = M*0 = 0
Fk = 400 N.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.