Asked by Tori
a projectile returns to its original height after 4.08 seconds, during which tie it travels 6.2 meters horizontally. If air resistance is ignored, what was the projectile's initial speed?
Answers
Answered by
Scott
horizontal velocity (vh) = 6.2 m / 4.08 s
initial vertical velocity (vv)
... = (4.08 s / 2) * g
(initial speed)^2 = vh^2 + vv^2
initial vertical velocity (vv)
... = (4.08 s / 2) * g
(initial speed)^2 = vh^2 + vv^2
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