Asked by Tori

a projectile returns to its original height after 4.08 seconds, during which tie it travels 6.2 meters horizontally. If air resistance is ignored, what was the projectile's initial speed?

Answers

Answered by Scott
horizontal velocity (vh) = 6.2 m / 4.08 s

initial vertical velocity (vv)
... = (4.08 s / 2) * g

(initial speed)^2 = vh^2 + vv^2
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions