Asked by jacky
I definately do not understand this problem.
If y varies directly with x, and y = 600 when x = 1000, find the constant of variation K.
If y is directonally (proportional) to x, then for every value of x there is a value for y multiplied by a constant value. So if was that we had for every value of x the value of y was three time x; then if x = 4, y=12; if x=6, y=18; if x=10,y=30 and so on. So we have an equation y=3x (y=Kx) and K would equal 3.
So for y=Kx
you have been given values for x and y in the question, you can find K.
If y varies directly with x, and y = 600 when x = 1000, find the constant of variation K.
If y is directonally (proportional) to x, then for every value of x there is a value for y multiplied by a constant value. So if was that we had for every value of x the value of y was three time x; then if x = 4, y=12; if x=6, y=18; if x=10,y=30 and so on. So we have an equation y=3x (y=Kx) and K would equal 3.
So for y=Kx
you have been given values for x and y in the question, you can find K.
Answers
Answered by
Henry
K = Y/X = 600/1000 = 0.6
Y/X = 0.6
Y = 0.6x
Y = kx
Y/X = 0.6
Y = 0.6x
Y = kx
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