Write a function rule to represent the situation:
The volume, V, remaining in a 243 ft^3 (cubed) pile of gravel decreases by .2 ft^3 (cubed) with each shovelful, s, of gravel spread in a walkway.
I think:
V=243 ft^3 - .2 ft^3s
The volume, V, remaining in a 243 ft^3 (cubed) pile of gravel decreases by .2 ft^3 (cubed) with each shovelful, s, of gravel spread in a walkway.
I think:
V=243 ft^3 - .2 ft^3s
Answers
Answered by
Steve
correct. I suspect that it would be better expressed as
V = 243-0.2s
where the axes are labeled
horizontal: shovelfuls
vertical: volume (ft^3)
V = 243-0.2s
where the axes are labeled
horizontal: shovelfuls
vertical: volume (ft^3)
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