xy^3-e^3x=y^2
12 answers
what are you trying to do?
I am trying to find the derivative
and do you mean
x y^3 - e^(3x) = y^2 ????
x y^3 - e^(3x) = y^2 ????
yes
Oh
If my guess is correct
x (3 y^2) dy/dx + y^3 - 3 e^(3x) = 2 y dy/dx
does that get you started?
If my guess is correct
x (3 y^2) dy/dx + y^3 - 3 e^(3x) = 2 y dy/dx
does that get you started?
I have the rest but where did y^3 come from?
d/dx (a b) = a db/dx + b da/dx
so
d/dx [ x (y^3) ] = x d(y^3)/dx) + y^3 dx/dx
so
d/dx [ x (y^3) ] = x d(y^3)/dx) + y^3 dx/dx
Ooo Okay and then after don't you bring all the (dy/dx) to one side of the equation.
After wouldn't it be x+y^3-3e^(3x)=2y(dy/dx)-3y^2(dy/dx)?
I guess. You have the idea. Now factor dy/dx out and divide I am not going to do the whole thing.
Okay Thank You I think I got the answer
There is a name for this type of problem, where you calculate dy/dx in terms of x AND y, without knowing or having to solve for y(x) first.
It is called implicit differentiation. You are on the right track with your solution.
It is called implicit differentiation. You are on the right track with your solution.