Asked by Armaan sijui
An athlete throws a javlin with velocity of 20m/s at angle of 15 degree with the horizontal . How far the javlin would hit the ground from the point of projection?
Answers
Answered by
bobpursley
the time in air is due to the initial vertical velocity, and gravity.
hf=hi+V*sin15*t-4.9t^2, find time t in air.
t=sqrt(20sin15/4.9)
now how far?
howfar=horizVelocity*timeinair
=20cos15*t
hf=hi+V*sin15*t-4.9t^2, find time t in air.
t=sqrt(20sin15/4.9)
now how far?
howfar=horizVelocity*timeinair
=20cos15*t
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