Let x be the number of ounces of substance A in the meal. Then, the number of ounces of substance C also equals x, and the number of ounces of substance B equals x/5 (one-fifth of x).
We can express the total nutrition provided by each substance in terms of x:
- Substance A provides 2% * x or 0.02x
- Substance B provides 15% * (x/5) or 0.15x
- Substance C provides 15% * x or 0.15x
To provide 100% of the required nutrition, we need the following equation to hold:
0.02x + 0.15(x/5) + 0.15x = 1
Solving for x:
0.02x + 0.03x + 0.15x = 1
0.20x = 1
x = 5
Thus, there should be 5 ounces of substance A, 5 ounces of substance C, and 5/5=1 ounce of substance B in the meal to provide 100% of the required nutrition.
Each ounce of a substance A supplies 2% of the nutrition a patient needs. Substance B supplies 15% of the required nutrition per ounce, and substance C supplies 15% of the required nutrition per ounce. If digestive restrictions require that substances A and C be given in equal amounts, and the amount of substance B be one-fifth of either of these other amounts, find the number of ounces of each substance that should be in the meal to provide 100% of the required nutrition.
1 answer
1 answer