Asked by thezombieunicorn
Hi, if anyone can help me with this problem I would greatly appreciate it. I understood all my other math problems except for this one. So if anyone could help walk me through the steps so I know for next time how to solve problems like this I would appreciate it :D.
1.Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(2,-2);y=-x-2
A.y=-2x
B.y=2x
C.y=1/2x
D.y=-x
1.Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(2,-2);y=-x-2
A.y=-2x
B.y=2x
C.y=1/2x
D.y=-x
Answers
Answered by
Damon
parallel to y = -1 x -2
has slope of -1
so of form
y = -1 x + b
now get b from that point.(2,-2)
-2 = -1(2) + b
-2 =-2 + b
b = 0
so
y = -x
has slope of -1
so of form
y = -1 x + b
now get b from that point.(2,-2)
-2 = -1(2) + b
-2 =-2 + b
b = 0
so
y = -x
Answered by
thezombieunicorn
Oh that makes senses now ,thank you for the help :)
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