Question

Would someone check my thinking please.

PVT of an ideal gas (nitrogen) are all given.

I've used PV=nRT rearranged to get the number of moles.

Then, U= 3/2nRT to get the internal energy of the sample.

Am I on the right track? Thanks.

Answer 1

well, all you can really define is changes
dU = n Cv dT
but if you say U = 0 at T = 0, I suppose that is ok
for a MONATOMIC ideal gas Cv = (3/2) R
BUT for diatomic (O2, N2 etc) Cv = (5/2)R
So you equation is ok only for changes of temperature (the U depends only on T) for a monatomic ideal g)as

Answer 2

Thanks Damon, I realise I didn't tell you what i'm asked to do!

I note your point about the start point for the equation. Thanks

Answer 3

OK, remember Nitrogen is normally diatomic, N2.