check this page
http://mathworld.wolfram.com/DeterminantExpansionbyMinors.html
It is presented better than we could do on this format
How is a determinant found using expansion by minors?
The only way I was taught to do it was by using diagonals.
5 answers
upper left * det of the rest without that row and column
- second down on left times det of everything without that row and column
+ third down on left times det of everything without that row and column
etc down that left column alternating signs until you get to the bottom left.
- second down on left times det of everything without that row and column
+ third down on left times det of everything without that row and column
etc down that left column alternating signs until you get to the bottom left.
In the trivial case of
a b
c d
it would be
a (d)
-c(b)
which you knew already
a b
c d
it would be
a (d)
-c(b)
which you knew already
thanks
now for the slightly less trivial
a b c
d e f
g h i
a times det
e f
h i
- d times det
b c
h i
+ g times det
b c
e f
which is
a (e i - h f)
-d(b i - h c)
+g(b f - e c )
which is
a e i - a h f - d b i + d h c + g b f - g e c
which is the same as you get using the diagonal method
a b c
d e f
g h i
a times det
e f
h i
- d times det
b c
h i
+ g times det
b c
e f
which is
a (e i - h f)
-d(b i - h c)
+g(b f - e c )
which is
a e i - a h f - d b i + d h c + g b f - g e c
which is the same as you get using the diagonal method