Asked by Anon
Hello,
If I need to find out how long it takes for an object acted on by a force takes to change speed by 1.0m/s^-1 and I know the magnitude of the force can I use the following equation?
a=v2-v1/t in order to establish the time taken?
If I need to find out how long it takes for an object acted on by a force takes to change speed by 1.0m/s^-1 and I know the magnitude of the force can I use the following equation?
a=v2-v1/t in order to establish the time taken?
Answers
Answered by
Damon
Yes, force = rate of change of momentum
= m a if mass is constant
a = (v2-v1)/t
Remember the parentheses.
= m a if mass is constant
a = (v2-v1)/t
Remember the parentheses.
Answered by
Anon
So if the acceleration was 60000 and I wanted to solve how many hours this would take I would:
a=(60000-0)/3600
Which is 16.2 hours? I’m alittle confused as this is how someone has shown me but I don’t understand why the time taken would be a (acceleration) rather than t?
Sorry I know it’s an odd question.
a=(60000-0)/3600
Which is 16.2 hours? I’m alittle confused as this is how someone has shown me but I don’t understand why the time taken would be a (acceleration) rather than t?
Sorry I know it’s an odd question.
Answered by
Bonny the Horse
Math is kwel
Answered by
JOYCE NAIGINO
Anon, you would use the mathematical expression which is got from Newton's second law of motion ie F=ma where F is the force acting on the object, m is the mass of the object and a is the acceleration of the object.This will help you to get the acceleration which you have said that =60000 m/s^2. You will then use your equation of:
a=(v2-v1)/t where (v2-v1)=1.0 m/s but not 1.o m/s^-1 as you had written in your question.ie, from a=(v2-v1)/t, it implies that 60000= 1/t, multiplying both sides by t: 60000 t =1, then divide both sides by 60000, ie (60000 t)/60000=1/60000: then t=1.67x10^-5 seconds =((1.67x10^-5)/3600) hours
a=(v2-v1)/t where (v2-v1)=1.0 m/s but not 1.o m/s^-1 as you had written in your question.ie, from a=(v2-v1)/t, it implies that 60000= 1/t, multiplying both sides by t: 60000 t =1, then divide both sides by 60000, ie (60000 t)/60000=1/60000: then t=1.67x10^-5 seconds =((1.67x10^-5)/3600) hours
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