Asked by olabamidele
Shows that each of the following sequences is an A.p and hence find the first 5 terms
3n+4,14-4n,4n-2. Solve it
3n+4,14-4n,4n-2. Solve it
Answers
Answered by
Damon
in general for AP the form is:
Xn = a + d(n-1)
Now look at 3n + 4
Xn = 4 + 3n
let a = 4
let d = 3
Xm = 4 + 3 (m-1)
where m = n+1
m = 1 to 5
4, 7 , 10 , 13 , 16
then 14 - 4 n
again
a = 14
d = -4
m = n+1
Xm = 14 - 4(m-1)
etc
Xn = a + d(n-1)
Now look at 3n + 4
Xn = 4 + 3n
let a = 4
let d = 3
Xm = 4 + 3 (m-1)
where m = n+1
m = 1 to 5
4, 7 , 10 , 13 , 16
then 14 - 4 n
again
a = 14
d = -4
m = n+1
Xm = 14 - 4(m-1)
etc
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