0.20 mm Hg = 0.20*133.322 Pa
mass density= (0.20*133.322*28.96)/(8.314*250)
= 0.0014 g/L
Forty miles above the earth's surface the temperature is 250 K and the pressure is only 0.20 mm Hg. What is the density of air (in grams per liter) at this altitude? (Assume the molar mass of air is 28.96 g/mol.)
PV=nRT
n/V= molar desity= P/RT
mass density= molar density*molmass
= P*(molmass)/RT
Watch your units.
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