Asked by L
                A toy car mass 0.05 kg ,on a ramp with no friction , begins at 0.7 meters high. At the bottom it collides inelastically with a toy truck mass 0.2 kg, at rest.  After the collision the car is at rest, what is the final velocity of the truck?
            
            
        Answers
                    Answered by
            Damon
            
    Ke of toy car =(1/2) m v^2 = m g h
so
v = sqrt(2gh) = sqrt(2*9.81*0.7)
v = 3.71 m/s
momentum = 0.05*v = 0.185 kg m/s
so
0.2 u = 0.185
u = 0.926 m/s
    
so
v = sqrt(2gh) = sqrt(2*9.81*0.7)
v = 3.71 m/s
momentum = 0.05*v = 0.185 kg m/s
so
0.2 u = 0.185
u = 0.926 m/s
                    Answered by
            Henry
            
    V^2 = Vo^2 + 2g*h.
V^2 = 0 + 19.6*0.7 = 13.72
V = 3.7 m/s = Velocity at the bottom of the ramp.
M1*V1 + M2*V2 = M1*0 + M2*V.
0.05*3.7 + M2*0 = 0 + 0.2V
0.185 = 0.2V
V = 0.925m/s = Final velocity of the truck.
    
V^2 = 0 + 19.6*0.7 = 13.72
V = 3.7 m/s = Velocity at the bottom of the ramp.
M1*V1 + M2*V2 = M1*0 + M2*V.
0.05*3.7 + M2*0 = 0 + 0.2V
0.185 = 0.2V
V = 0.925m/s = Final velocity of the truck.
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