Question

Na2CO3 + 2HCL  CO2 + H2O + 2NaCl
Reaction Ration is 1:2
Calculate how many moles of HCl are present in the average volume of HCl at the end-point.
Avg. volume is 0.0182L

Answer 1

mols = M x L = ? You have L but no M
or
mols Na2CO3 = grams/molar mass = ? Then mols HCl = mols Na2CO3 x 2 x L. Again, you have L HCl but no mols Na2CO3.