Asked by Young

Two satellites S1 and S2 orbit around a planet P in circular orbits of radii r1 = 5.25 106 m, and r2 = 8.60 106 m respectively. If the speed of the first satellite S1 is 1.65 104 m/s, what is the speed of the second satellite S2?

m/s

Answers

Answered by Young
A = v^2/r
A = (1.65*10^4)^2/(5.25*10^6)
A = 51.857
A = G(m/r^2)
m = A*r^2/G
G = 6.67*10^-11
m = 51.857*(5.25*10^6)^2/6.67*10^-11
m = 2.143*10^25
------------------------------------
A = G(m/r^2)
A = 6.67*10^-11(2.143*10^25/(8.6*10^6)^2)
A = 19.33
A = v^2/r
(A*r)^(1/2) = v (19.33*8.6*10^6)^1/2
v = 12892.13299 m/s^2
Answered by Scott
the centripetal force (gravity) is inversely proportional to the square of the orbit radius

(V1^2 / R1) (R1 / R2)^2 = V2^2 / R2

V1^2 R1 / R2 = V2^2

1.65E4^2 * 5.25E6 / 8.60E6 = V2^2


be aware of significant figures
Answered by Anonymous
6. Two satellites are in orbit around a planet. Satellite Si takes 20 days to orbit the planet at a distance of 2X105 km from the center of the planet. Satellite S2 takes 160 days to orbit the planet. What is the distance of satellite S2 from the center of the planet?
Answered by UNKNOWN
I Wann the answer.
Answered by Anonymous
Ok so what you need to do first is find the mass of the planet, this can be found using the equation v = ((GM)/r)^(1/2), where G is the constant 6.67*10^-11, and v and r are your givens for one satellite.

After finding the mass you can use the same equation to solve for your speed of the other satellite.
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