Asked by Buma
There is gas in a gas container. A valve on the container will be opened and a quarter of the gas quantity will be released to the outer range. Due to this process the temperature of the gas will be decreased by 20%. What is the decrease of the gas pressure?
Answers
Answered by
bobpursley
p1v1=nRT
P2V2=.75nRt2
V1=V2
P2=.75nRT2P1/nRT1
but T2=.8T1
P2/P1=.75*.8=.6
soPressure 2 is sixty percent of the original pressure.
check my work
P2V2=.75nRt2
V1=V2
P2=.75nRT2P1/nRT1
but T2=.8T1
P2/P1=.75*.8=.6
soPressure 2 is sixty percent of the original pressure.
check my work