Question
What mass of calcium carbonate (CaCO3) is required to neutralize 20 ML of sulphuric acid (H2SO4) of concentration 490 g/L?
Answers
bobpursley
BALANCE the equation
CaCO3 + H2SO4>>>CaSO4 + H2O + CO2
so for every mole of sulfuric acid you need one mole of calcium carbonate.
Moles Sulfuric acid= 20/1000*490/molmassH2SO4
=20/1000*490/98=.1 moles check that.
mass of CaCO3: .1moles*molmass=.1*100=10grams.
check my math
CaCO3 + H2SO4>>>CaSO4 + H2O + CO2
so for every mole of sulfuric acid you need one mole of calcium carbonate.
Moles Sulfuric acid= 20/1000*490/molmassH2SO4
=20/1000*490/98=.1 moles check that.
mass of CaCO3: .1moles*molmass=.1*100=10grams.
check my math