Question
6sin(2x)+3=0
How do you find the smallest value of x in the interval 0≤x≤π for which y=0?
My work so far:
6sin(2x)=-3
sin(2x)=-1/2
The answer should be 7π/12, or 1.83
Thanks in advance!
How do you find the smallest value of x in the interval 0≤x≤π for which y=0?
My work so far:
6sin(2x)=-3
sin(2x)=-1/2
The answer should be 7π/12, or 1.83
Thanks in advance!
Answers
Steve
sin π/6 = 1/2
since sine is negative is QIII and QIV, we have
2x = 7π/6 or 11π/6
that should help.
since sine is negative is QIII and QIV, we have
2x = 7π/6 or 11π/6
that should help.