mols Fe(NH4)2(SO4)2.6H2O = grams/molar mass = ?. Then (A) = mols /L = ? Let's call this Y.
(B) = (A) x (5.00/100) = ?
(C) = done the same way as (B).
0.1825 g of Fe(NH4)2(SO4)2•6H2O is dissolved in 250.00 mL of solution; this is Solution A. 5.00 mL of Solution A is transferred to another flask, and it is diluted to a total of 100.0 mL to make another solution, which is Solution B. Next, 3.00 mL of Solution B is diluted to a total of 10.0 mL to make Solution C.
a) what is the molar concentration of Solution A?
b) what is the molar concentration of Solution B?
c) what is the molar concentration of Solution C?
1 answer