a body is moving with a initial velocity of 2m/s with constant acceleration of2m/s^2.another body starts from rest with constant acceleration of 6m/s^2.find how far from the second particles overtake the first

Answer 1

x = 2 t + (1/2)(2) t^2
and
x = (1/2)(6) t^2
so
3 t^2 = 2 t + t^2
2 t^2 -2 t = 0
t (2 t - 2) = 0

t = 1
x = 3