Asked by eve
given" triangle KL, LM=12 measure of angle k=60 mesure of angle m=45 find the perimeter
is got the angle L is 75 (sum of angles therom) land then I drew a line from point k to line LM the line forms a right angl (by construction). the point that meets LM is point O and angle OKM is 45 degrees. OKM is a 45 45 90 triangle meaning that its also and iosolese triangle and that the hypotuluse (KM) is x/sqrt/ but now im stuck and dont know what to do. im trying to fing a therom that would help me here but i cant find one. can you help
is got the angle L is 75 (sum of angles therom) land then I drew a line from point k to line LM the line forms a right angl (by construction). the point that meets LM is point O and angle OKM is 45 degrees. OKM is a 45 45 90 triangle meaning that its also and iosolese triangle and that the hypotuluse (KM) is x/sqrt/ but now im stuck and dont know what to do. im trying to fing a therom that would help me here but i cant find one. can you help
Answers
Answered by
eve
I really need help :(
Answered by
Steve
using the law of sines, you can find the other sides, since
12/sin60° = KM/sin75° = KL/sin45°
Then just add up the sides.
Your idea will work, but you will need to note that
(12-x)/x = sin15°
you can then solve for x using the half-angle formula, but the expressions involve more and more complex radicals.
12/sin60° = KM/sin75° = KL/sin45°
Then just add up the sides.
Your idea will work, but you will need to note that
(12-x)/x = sin15°
you can then solve for x using the half-angle formula, but the expressions involve more and more complex radicals.
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