Asked by NUNYA

The local reader’s club has a set of 36 hardback books and a set of 30 paperbacks. Each set can be divided equally among the club members. What is the greatest possible number of club members?
Answered by Ms. Sue
What is the largest common factor?

Answered by NUNYA
idk, uhm 6?
Answered by Ms. Sue
Right. So the greatest number of club members is 6.

Answered by NUNYA
thanks!
Answered by Ms. Sue
You're welcome.
Answered by OOF
if anybody has all the answers please tell me i need to get all of the questions right so i get a good score on the unit 3 math test
Answered by db
please i need the anwers
Answered by GET YO ANSWERS
Ok hey yall im feeling nice so yall are getting the answers...
1. D: 35/30<22/12
2. B: 6^5
3. A: -16
4.D: -1
5.D: 1,012
6.A: 189
7. B: 23
8.A: 9
9.D: 8
10.D: A=1/4, B=7/16,C=5/8,D=3/4
11.D: 46/7
12.C: 3 1/4, 13/4
13. D: A=-0.7,B=-9/16,C=-.4,D=5/16
14.D:Felisha
15.C:4
16.B:4,140
17. C: 3,9
18.A: 13/25
19. A: 4 1/3
20.B: 0.3125
21.D: 31/100
22.B:6
THESE ANSWERS ARE FROM THE CONECSUS LESSON FOR MATH IF ANY ARE WRONG PLS LEMME KNOW :3
Answered by PLEASE HELP ME
Ms Sue? Can you help?? Plsss
Answered by ✨💅
dont mind me just looking
Answered by ✨💅
also yes she is wrong
Answered by rara
plz help me with my unit test : /
Answered by zookeeper💋🌹💕😍😘💖
That was so much help yeeeter skeeeeetr
Answered by CONNEXUS BOI
The number of hardback books in a set = 49

The number of paperbacks in a set =21

Since each set can be divided equally among the club members then to find the greatest possible number of club members, we need to find the greatest common factor of 49 and 21.

The prime factorization of 49 and 21 :
49 = 7 x 7
21 = 3 x 7

We can see that the greatest common factor of 49 and 21 =7

Thus, the greatest possible number of club members is 7
Answered by CONNEXUS BOI
oh also GET YO ANSWERS is incorrect don't listen to them
Answered by CONNEXUS BOI
i just realized i put the answer for a different question. oops well if ur question is this then listen to me otherwise don't

The local readers’ club has a set of 49 hardback books and a set of 21 paperbacks. each set can be divided equally among the club members. what is the greatest possible number of club members?14 21 147 7
Answered by HALP MEH
1. C: 15/25>22/44
2. B: 7^5
3. C: -73
4. C: -27
5. A: 344
6. D: 1.34 x 10^1
7. D: 1,070
8. C: 100
9. B: 41
10. B: 6
11. C: 7
12. D: 1/4, 7/16, 5/8, 3/4
13. B: 35/8
14. A: 3 2/3; 11/3
15. B: -0.4, -0.7, -5/16, -9/16
16. D: Amanda
17. B: 0
18. A: 9,180 and 4,932
19. B: 2, 3
20. A: 7/15
21. C: 3 1/3
22. A: 0.36
23 A: 29/100
24 B: 6
The rest are questions you have to answer in your own words. I hope this helped🥱😁!
Answered by connexus
halp did you take the test and see the answer
Answered by HALP MEH
Why u asking?
Answered by HALP MEH
Welp I got to go buh bye
Answered by Brownskin_brownie
help meh are your answers right
Answered by nobody
no
Answered by Critty
WE NEED 2021 ANSWERS
There are no AI answers yet. The ability to request AI answers is coming soon!