Question
Somebody please help me. A friend of mine is trying to figure this out and I don't know how to help her because I haven't learned this.
A student heats a 15.0 gram metallic sphere of unknown composition to a temperature of 98°C. The sphere is transferred to a calorimeter containing 100. mL of water at a temperature of 25.0°C. The student observes that the resulting temperture of both the water and the object is 27.1°C after the object is submerged.
1. Describe, in terms of the object and the water, the flow of heat energy that took place during the experiment.
2. Calculate the amount of heat energy gained by the water in the calorimeter.
3. Using the quantity of heat calculated in the previous question, determine the specific heat of the object.
A student heats a 15.0 gram metallic sphere of unknown composition to a temperature of 98°C. The sphere is transferred to a calorimeter containing 100. mL of water at a temperature of 25.0°C. The student observes that the resulting temperture of both the water and the object is 27.1°C after the object is submerged.
1. Describe, in terms of the object and the water, the flow of heat energy that took place during the experiment.
2. Calculate the amount of heat energy gained by the water in the calorimeter.
3. Using the quantity of heat calculated in the previous question, determine the specific heat of the object.
Answers
Anonymous
2. Q = mcΔT?
Anonymous
I don't know how to calculate this, please help me!
DrBob222
With two anonymous names I don't know the difference; however, I assume the first one is answering the question 2 and the others one is saying s/he doesn't know how to use it.
q = heat gained
m = mass water. 100 mL water has a mass of 100 grams.
c = specific heat water which is 4.184 J/g*C
delta T is change in T which goes from 25.0 C to 27.1 C or 2.1.
q = heat gained
m = mass water. 100 mL water has a mass of 100 grams.
c = specific heat water which is 4.184 J/g*C
delta T is change in T which goes from 25.0 C to 27.1 C or 2.1.
Anonymous
887.8